6[5y-(3y-1)]=4(3y-7)

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Solution for 6[5y-(3y-1)]=4(3y-7) equation:


Simplifying
6[5y + -1(3y + -1)] = 4(3y + -7)

Reorder the terms:
6[5y + -1(-1 + 3y)] = 4(3y + -7)
6[5y + (-1 * -1 + 3y * -1)] = 4(3y + -7)
6[5y + (1 + -3y)] = 4(3y + -7)

Reorder the terms:
6[1 + 5y + -3y] = 4(3y + -7)

Combine like terms: 5y + -3y = 2y
6[1 + 2y] = 4(3y + -7)
[1 * 6 + 2y * 6] = 4(3y + -7)
[6 + 12y] = 4(3y + -7)

Reorder the terms:
6 + 12y = 4(-7 + 3y)
6 + 12y = (-7 * 4 + 3y * 4)
6 + 12y = (-28 + 12y)

Add '-12y' to each side of the equation.
6 + 12y + -12y = -28 + 12y + -12y

Combine like terms: 12y + -12y = 0
6 + 0 = -28 + 12y + -12y
6 = -28 + 12y + -12y

Combine like terms: 12y + -12y = 0
6 = -28 + 0
6 = -28

Solving
6 = -28

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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